2[d-(3d+19)+16]=2(d+3)

Solution for 2[d-(3d+19)+16]=2(d+3) equation:

Simplifying
2[d + -1(3d + 19) + 16] = 2(d + 3)

Reorder the terms:
2[d + -1(19 + 3d) + 16] = 2(d + 3)
2[d + (19 * -1 + 3d * -1) + 16] = 2(d + 3)
2[d + (-19 + -3d) + 16] = 2(d + 3)

Reorder the terms:
2[-19 + 16 + d + -3d] = 2(d + 3)

Combine like terms: -19 + 16 = -3
2[-3 + d + -3d] = 2(d + 3)

Combine like terms: d + -3d = -2d
2[-3 + -2d] = 2(d + 3)
[-3 * 2 + -2d * 2] = 2(d + 3)
[-6 + -4d] = 2(d + 3)

Reorder the terms:
-6 + -4d = 2(3 + d)
-6 + -4d = (3 * 2 + d * 2)
-6 + -4d = (6 + 2d)

Solving
-6 + -4d = 6 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-6 + -4d + -2d = 6 + 2d + -2d

Combine like terms: -4d + -2d = -6d
-6 + -6d = 6 + 2d + -2d

Combine like terms: 2d + -2d = 0
-6 + -6d = 6 + 0
-6 + -6d = 6

Add '6' to each side of the equation.
-6 + 6 + -6d = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -6d = 6 + 6
-6d = 6 + 6

Combine like terms: 6 + 6 = 12
-6d = 12

Divide each side by '-6'.
d = -2

Simplifying
d = -2